Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams? Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams? Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions? Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the circular motion at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the stone's circular motion at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to keep the stone moving in a circle at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for the same speed.
Q. A stone is tied to a string and whirled in a vertical circle of radius 1 m. What is the minimum speed at the top of the circle to keep the stone in circular motion?
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
Solution
At the top, centripetal force = weight. mv²/r = mg. v² = rg. v = √(1*9.8) ≈ 3.13 m/s.
Q. A store increases the price of a product by 25% and then offers a 20% discount. If the original price was $80, what is the final price after the discount?
A.
$80
B.
$85
C.
$90
D.
$95
Solution
New price after increase = 80 + (25% of 80) = 80 + 20 = $100. Discount = 20% of 100 = 20. Final price = 100 - 20 = $80.
Q. A store increases the price of a product by 25% and then offers a discount of 20%. If the original price was $80, what is the final price after the discount?
A.
$72
B.
$76
C.
$80
D.
$64
Solution
New price after increase = 80 + 0.25 * 80 = 100. Discount = 20% of 100 = 20. Final price = 100 - 20 = $80.
Q. A store increases the price of an item by 25% and then offers a discount of 20% on the new price. What is the final price if the original price was $80?
A.
$70
B.
$75
C.
$80
D.
$85
Solution
New price after increase = 80 * 1.25 = $100. Discount = 20% of 100 = $20. Final price = 100 - 20 = $80.
Q. A store offers a 10% discount on a product that costs $200. If the store then applies an additional 5% discount on the already discounted price, what is the final selling price?
A.
$180
B.
$190
C.
$185
D.
$175
Solution
First discount: 200 - 10% of 200 = 200 - 20 = 180. Second discount: 180 - 5% of 180 = 180 - 9 = 171.
Q. A store offers a 25% discount on a jacket that is originally priced at $80. If the store then increases the price by 10% after the discount, what is the final price of the jacket?
A.
$70
B.
$75
C.
$78
D.
$80
Solution
Discounted price = $80 - (25% of $80) = $80 - $20 = $60. After a 10% increase, final price = $60 + (10% of $60) = $60 + $6 = $66.
Q. A store offers a 30% discount on a jacket originally priced at $200. If the store then increases the price by 10% after the discount, what is the final price?
Q. A store offers a 30% discount on a jacket originally priced at $200. If the store then increases the price by 10% after the discount, what is the final price of the jacket?
Q. A store offers a 30% discount on a jacket originally priced at $300. If an additional 10% discount is applied on the discounted price, what is the final price?
Q. A store offers a 30% discount on a jacket that is originally priced at $200. If the store then applies an additional 10% discount on the already discounted price, what is the final selling price? (2023)
A.
$140
B.
$150
C.
$160
D.
$170
Solution
First discount: $200 - (30% of $200) = $200 - $60 = $140. Second discount: $140 - (10% of $140) = $140 - $14 = $126.
