Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A state legislature meets for 90 days in a year. If each member is paid $200 per day, what is the total amount paid to a legislature with 50 members for the entire session?

A. $900,000
B. $1,000,000
C. $1,100,000
D. $1,200,000

Solution

Total payment = 50 members * $200/day * 90 days = $1,000,000.

Correct Answer: B — $1,000,000

Q. A stitch in time saves nine. If you address problems early, what can be inferred?

A. Problems will disappear
B. Early action prevents bigger issues
C. Delaying action is beneficial
D. All problems are easy to fix

Solution

The saying implies that taking timely action can prevent larger problems later, hence early intervention is beneficial.

Correct Answer: B — Early action prevents bigger issues

Q. A stock price increased from $80 to $100. What is the percentage increase in the stock price? (2023)

A. 20%
B. 25%
C. 30%
D. 15%

Solution

Percentage Increase = ((New Price - Old Price) / Old Price) * 100 = ((100 - 80) / 80) * 100 = 25%.

Correct Answer: B — 25%

Q. A stone is dropped from a height of 20 m. How long does it take to reach the ground?

A. 2 s
B. 1 s
C. 3 s
D. 4 s

Solution

Using h = (1/2)gt², where h = 20 m and g = 9.8 m/s², we have 20 = (1/2)*9.8*t². Solving gives t² = 4.08, so t ≈ 2 s.

Correct Answer: A — 2 s

Q. A stone is dropped from a height of 20 m. How long will it take to reach the ground?

A. 2 s
B. 1 s
C. 3 s
D. 4 s

Solution

Using h = (1/2)gt², where h = 20 m and g = 9.8 m/s², we have 20 = (1/2)*9.8*t². Solving gives t² = 4.08, so t ≈ 2 s.

Correct Answer: A — 2 s

Q. A stone is dropped from a height of 45 m. How far will it have fallen after 2 seconds?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(2²) = 19.6 m.

Correct Answer: C — 30 m

Q. A stone is dropped from a height of 45 m. How far will it have fallen after 3 seconds?

A. 10.5 m
B. 20 m
C. 30 m
D. 40.5 m

Solution

Distance fallen (s) = (1/2)gt² = (1/2)(9.8)(3²) = 44.1 m.

Correct Answer: D — 40.5 m

Q. A stone is dropped from a height of 45 m. How far will it travel horizontally if it is projected horizontally with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall t = √(2h/g) = √(90/9.8) ≈ 4.27 s; horizontal distance = 10 * 4.27 ≈ 42.7 m.

Correct Answer: C — 40 m

Q. A stone is dropped from a height of 45 m. How far will it travel horizontally if it is thrown horizontally with a speed of 10 m/s?

A. 20 m
B. 30 m
C. 40 m
D. 50 m

Solution

Time to fall (t) = √(2h/g) = √(2*45/9.8) ≈ 3 s; horizontal distance = v*t = 10*3 = 30 m.

Correct Answer: B — 30 m

Q. A stone is dropped from a height of 45 m. How long does it take to reach the ground?

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = (1/2)gt², we have 45 = (1/2)(9.8)t², solving gives t ≈ 4.3 s.

Correct Answer: B — 4 s

Q. A stone is dropped from a height of 80 m. How long does it take to hit the ground?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Time (t) = √(2h/g) = √(2*80/9.8) = 4.04 s.

Correct Answer: A — 4 s

Q. A stone is dropped from a height of 80 m. How long will it take to reach the ground?

A. 2 s
B. 4 s
C. 6 s
D. 8 s

Solution

Using h = (1/2)gt², we get t = √(2h/g) = √(2*80/9.8) = 4.04 s.

Correct Answer: B — 4 s

Q. A stone is thrown downward with an initial velocity of 5 m/s from a height of 45 m. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the equation of motion: h = ut + 0.5gt². 45 = 5t + 0.5 * 10 * t². Solving the quadratic gives t = 3 s.

Correct Answer: B — 4 s

Q. A stone is thrown downward with an initial velocity of 5 m/s from a height of 45 m. How long will it take to hit the ground? (2020)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the equation of motion: h = ut + 0.5gt². Solving for t gives t ≈ 4 seconds.

Correct Answer: B — 4 s

Q. A stone is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2023)

A. 3 s
B. 4.5 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, we have 45 = 0.5 * 10 * t^2. Solving gives t^2 = 9, so t = 3 s.

Correct Answer: A — 3 s

Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long does it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long does it take to hit the ground? (g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using h = 0.5 * g * t^2, rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

Q. A stone is thrown horizontally from the top of a cliff 45 m high. How long will it take to hit the ground? (Assume g = 10 m/s²)

A. 3 s
B. 4 s
C. 5 s
D. 6 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2 * 45 / 10) = sqrt(9) = 3 s.

Correct Answer: B — 4 s

Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land?

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = horizontal speed * time. Assuming horizontal speed = 10 m/s, distance = 10 m/s * 4.04 s = 40.4 m.

Correct Answer: B — 40 m

Q. A stone is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will the stone land if it is thrown with a speed of 10 m/s?

A. 20 m
B. 40 m
C. 60 m
D. 80 m

Solution

Time to fall = √(2h/g) = √(2*80/9.8) ≈ 4.04 s. Horizontal distance = speed * time = 10 m/s * 4.04 s ≈ 40 m.

Correct Answer: B — 40 m

Q. A stone is thrown horizontally from the top of a cliff 80 m high. How long does it take to hit the ground? (g = 10 m/s²)

A. 4 s
B. 8 s
C. 10 s
D. 12 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2 * 80 / 10) = sqrt(16) = 4 s.

Correct Answer: A — 4 s

Q. A stone is thrown in a circular path with a radius of 3 m. If the stone completes 4 revolutions in 8 seconds, what is the angular speed?

A. π/2 rad/s
B. π rad/s
C. 2π rad/s
D. 4π rad/s

Solution

Angular speed (ω) = Total angle / Time = (4 * 2π) / 8 = π rad/s.

Correct Answer: B — π rad/s

Q. A stone is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

A. 10 m
B. 20 m
C. 30 m
D. 40 m

Solution

Maximum height (H) = (u²)/(2g) = (20²)/(2*9.8) ≈ 20.4 m.

Correct Answer: C — 30 m

Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height?

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

Q. A stone is thrown vertically upward with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Correct Answer: B — 2 s

Q. A stone is thrown vertically upwards with a speed of 15 m/s. How long will it take to reach the highest point? (Take g = 10 m/s²) (2023)

A. 1.5 s
B. 2 s
C. 3 s
D. 4 s

Solution

Time to reach highest point = u/g = 15/10 = 1.5 s.

Correct Answer: B — 2 s

Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Assume g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: time = (final velocity - initial velocity) / g. At maximum height, final velocity = 0. Time = (0 - 20) / -10 = 2 s.

Correct Answer: B — 2 s

Q. A stone is thrown vertically upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (g = 10 m/s²)

A. 1 s
B. 2 s
C. 3 s
D. 4 s

Solution

Using the formula: v = u - gt. At maximum height, v = 0. So, 0 = 20 - 10t. Solving gives t = 2 s.

Correct Answer: B — 2 s

Q. A stone is tied to a string and swung in a vertical circle. At the highest point, the tension in the string is 5 N and the weight of the stone is 10 N. What is the speed of the stone at the highest point if the radius of the circle is 2 m?

A. 2 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

At the highest point, T + mg = mv²/r. 5 + 10 = (m*v²)/2. Solving gives v = 4 m/s.

Correct Answer: C — 4 m/s

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