Major Competitive Exams

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Major Competitive Exams

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Major Competitive Exams MCQ & Objective Questions

Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.

What You Will Practise Here

Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams

Exam Relevance

The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.

Common Mistakes Students Make

Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam

FAQs

Question: How can I improve my performance in Major Competitive Exams?
Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.

Question: What types of questions should I focus on for these exams?
Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.

Question: Are there specific strategies for tackling objective questions?
Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!

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Q. A spherical shell of radius R carries a uniform charge Q. What is the electric field inside the shell?

A. Q/(4πε₀R²)
B. 0
C. Q/(4πε₀R)
D. Q/(4πε₀)

Solution

By Gauss's law, the electric field inside a uniformly charged spherical shell is zero.

Correct Answer: B — 0

Q. A spherical shell of radius R carries a uniform surface charge density σ. What is the electric field inside the shell?

A. 0
B. σ/ε₀
C. σ/2ε₀
D. σ/4ε₀

Solution

By Gauss's law, the electric field inside a uniformly charged spherical shell is zero.

Correct Answer: A — 0

Q. A sports event awards medals to the top 3 finishers. If the first place receives a gold medal, the second place receives a silver medal, and the third place receives a bronze medal, what is the ratio of gold to silver to bronze medals awarded? (2021)

A. 1:1:1
B. 1:2:3
C. 1:1:2
D. 1:2:1

Solution

The ratio of gold to silver to bronze medals is 1:1:1 since each position gets one medal.

Correct Answer: A — 1:1:1

Q. A sports event awards medals to the top 3 finishers. If there are 12 participants, how many different ways can the medals be awarded?

A. 220
B. 1320
C. 1728
D. 1440

Solution

The number of ways to award medals is calculated using permutations: P(12, 3) = 12! / (12-3)! = 12 * 11 * 10 = 1320.

Correct Answer: B — 1320

Q. A sports event has 3 categories of awards: Gold, Silver, and Bronze. If there are 10 Gold awards, 15 Silver awards, and 20 Bronze awards, what is the total number of awards given?

A. 30
B. 40
C. 50
D. 60

Solution

Total awards = 10 + 15 + 20 = 45.

Correct Answer: C — 50

Q. A sports event has a total prize pool of $5,000. If the first place gets 50% of the prize pool, how much does the first place winner receive?

A. $2,500
B. $3,000
C. $2,000
D. $1,500

Solution

50% of $5,000 is $2,500.

Correct Answer: A — $2,500

Q. A sports team has a win-loss record of 8 wins and 2 losses. What is the winning percentage of the team? (2022)

A. 80%
B. 75%
C. 70%
D. 85%

Solution

Winning percentage = (wins / total games) × 100 = (8 / (8 + 2)) × 100 = 80%.

Correct Answer: A — 80%

Q. A sports team wins 70% of its matches. If they played 50 matches, how many matches did they win? (2023)

A. 30
B. 35
C. 40
D. 45

Solution

Matches won = 70% of 50 = 0.7 * 50 = 35 matches.

Correct Answer: B — 35

Q. A sports team won 75% of their games. If they played 40 games, how many games did they win? (2023)

A. 30
B. 25
C. 35
D. 20

Solution

Games won = 75% of 40 = 0.75 × 40 = 30 games.

Correct Answer: A — 30

Q. A sports team won 75% of their matches. If they played 40 matches, how many matches did they win? (2022)

A. 30
B. 25
C. 35
D. 20

Solution

Matches won = 75% of 40 = 0.75 × 40 = 30 matches.

Correct Answer: A — 30

Q. A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.5 m?

A. 50 N
B. 100 N
C. 150 N
D. 200 N

Solution

Using Hooke's law, F = kx = 200 N/m * 0.5 m = 100 N.

Correct Answer: B — 100 N

Q. A spring has a spring constant of 200 N/m. How much force is required to stretch the spring by 0.1 m?

A. 5 N
B. 10 N
C. 15 N
D. 20 N

Solution

Using Hooke's law, F = kx = 200 N/m * 0.1 m = 20 N.

Correct Answer: A — 5 N

Q. A spring is compressed by 0.1 m and has a spring constant of 200 N/m. What is the potential energy stored in the spring? (2019)

A. 1 J
B. 2 J
C. 0.5 J
D. 4 J

Solution

Potential Energy (PE) = 1/2 * k * x^2 = 1/2 * 200 N/m * (0.1 m)^2 = 1 J

Correct Answer: A — 1 J

Q. A spring is compressed by 0.2 m and has a spring constant of 300 N/m. What is the potential energy stored in the spring?

A. 6 J
B. 12 J
C. 18 J
D. 24 J

Solution

Potential Energy in spring (PE) = 0.5 × k × x² = 0.5 × 300 N/m × (0.2 m)² = 0.5 × 300 × 0.04 = 6 J.

Correct Answer: B — 12 J

Q. A spring is compressed by 0.2 m and has a spring constant of 500 N/m. What is the potential energy stored in the spring? (2023)

A. 10 J
B. 5 J
C. 20 J
D. 2 J

Solution

Potential Energy in Spring (PE) = 1/2 kx^2 = 1/2 * 500 N/m * (0.2 m)^2 = 10 J

Correct Answer: A — 10 J

Q. A spring is compressed by 0.5 m and has a spring constant of 200 N/m. What is the potential energy stored in the spring?

A. 25 J
B. 50 J
C. 100 J
D. 200 J

Solution

Potential Energy (PE) = 0.5 * k * x² = 0.5 * 200 N/m * (0.5 m)² = 25 J.

Correct Answer: A — 25 J

Q. A spring obeys Hooke's law. If the spring constant is doubled, what happens to the elongation for the same applied force?

A. Elongation doubles
B. Elongation halves
C. Elongation remains the same
D. Elongation quadruples

Solution

According to Hooke's law, elongation is inversely proportional to the spring constant; thus, if the spring constant is doubled, the elongation halves.

Correct Answer: B — Elongation halves

Q. A spring stretches 0.1 m when a force of 10 N is applied. What is the spring constant?

A. 100 N/m
B. 50 N/m
C. 200 N/m
D. 10 N/m

Solution

Using Hooke's Law, F = kx, we have k = F/x = 10 N / 0.1 m = 100 N/m.

Correct Answer: A — 100 N/m

Q. A spring stretches 5 cm when a load of 10 N is applied. What is the spring constant?

A. 200 N/m
B. 100 N/m
C. 50 N/m
D. 25 N/m

Solution

Using Hooke's law, k = F/x = 10 N / 0.05 m = 200 N/m.

Correct Answer: B — 100 N/m

Q. A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the potential energy stored in the spring?

A. 1 J
B. 2 J
C. 3 J
D. 4 J

Solution

Potential Energy = 0.5 × k × x² = 0.5 × 200 N/m × (0.1 m)² = 1 J.

Correct Answer: A — 1 J

Q. A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the work done in compressing the spring?

A. 1 J
B. 2 J
C. 3 J
D. 4 J

Solution

Work done = 0.5 × k × x^2 = 0.5 × 200 N/m × (0.1 m)^2 = 1 J.

Correct Answer: A — 1 J

Q. A spring with a spring constant of 200 N/m is compressed by 0.5 m. What is the potential energy stored in the spring?

A. 25 J
B. 50 J
C. 100 J
D. 200 J

Solution

Potential Energy in spring = 0.5 × k × x² = 0.5 × 200 N/m × (0.5 m)² = 25 J.

Correct Answer: B — 50 J

Q. A spring with a spring constant of 200 N/m is compressed by 0.5 m. What is the work done in compressing the spring?

A. 25 J
B. 50 J
C. 100 J
D. 200 J

Solution

Work done = 0.5 × k × x² = 0.5 × 200 N/m × (0.5 m)² = 25 J.

Correct Answer: B — 50 J

Q. A square has a perimeter of 40 cm. What is the area of the square?

A. 100 cm²
B. 200 cm²
C. 150 cm²
D. 250 cm²

Solution

Perimeter of a square = 4 × side. Thus, 40 = 4 × side, giving side = 10 cm. Area = side² = 10² = 100 cm².

Correct Answer: A — 100 cm²

Q. A square has a perimeter of 40 cm. What is the length of one side?

A. 10 cm
B. 8 cm
C. 12 cm
D. 6 cm

Solution

Perimeter = 4 × side, so side = Perimeter / 4 = 40 cm / 4 = 10 cm.

Correct Answer: A — 10 cm

Q. A square has a perimeter of 48 cm. What is the area of the square?

A. 144 cm²
B. 64 cm²
C. 36 cm²
D. 100 cm²

Solution

Perimeter of a square = 4 × side. Thus, 48 = 4 × side, giving side = 12 cm. Area = side² = 12² = 144 cm².

Correct Answer: A — 144 cm²

Q. A square has a perimeter of 64 cm. What is the length of one side of the square?

A. 16 cm
B. 12 cm
C. 14 cm
D. 8 cm

Solution

The perimeter of a square is given by P = 4s, where s is the length of one side. Therefore, 4s = 64 cm, leading to s = 16 cm.

Correct Answer: A — 16 cm

Q. A square room has a perimeter of 40 meters. What is the length of one side of the room?

A. 8 meters
B. 10 meters
C. 12 meters
D. 15 meters

Solution

Perimeter = 4 * side, so side = perimeter/4 = 40/4 = 10 meters.

Correct Answer: B — 10 meters

Q. A state legislature has 150 members. If 1/4 of them are new members, how many new members are there?

A. 30
B. 35
C. 40
D. 45

Solution

1/4 of 150 is 150 / 4 = 37.5, rounded down to 37.

Correct Answer: A — 30

Q. A state legislature has 300 members. If 1/5 of them are elected every year, how many members are elected each year?

A. 50
B. 60
C. 70
D. 80

Solution

1/5 of 300 is 300 / 5 = 60.

Correct Answer: A — 50

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