According to Charles's Law, volume and temperature are directly proportional at constant pressure.

If ΔH is positive and ΔS is negative, ΔG will be positive.

If ΔH is positive and ΔS is negative, ΔG will always be positive.

Boyle's Law states that for a given mass of gas at constant temperature, the volume is inversely proportional to the pressure.

The gravitational potential becomes zero at infinity, as V approaches zero as r approaches infinity.

The gravitational forces exerted by both masses cancel each other out at the midpoint.

To find local minima, we find f'(x) = 3x^2 - 6x. Setting f'(x) = 0 gives x = 0 and x = 2. Checking the second derivative, f''(2) = 6 > 0, so (2, 1) is a local minimum.

The gravitational potential is constant along an equipotential surface.

The gravitational potential energy is considered zero at infinity.

The gravitational potential is considered zero at infinity.

According to Charles's Law, the volume of a gas approaches zero at absolute zero, which is 0 K.

Set ΔG = 0: 0 = ΔH - TΔS; T = ΔH/ΔS = 50 kJ / 0.1 kJ/K = 500 K.

The Gibbs Free Energy changes from negative to positive at the transition temperature, where the system shifts from one phase to another.

According to Charles's Law, the volume of a gas approaches zero at absolute zero, which is -273.15 °C.

According to Charles's Law, the volume of a gas approaches zero at absolute zero, which is 0 K.

Using v_rms = sqrt(3RT/M), we solve for T: T = (v_rms^2 * M) / (3R) = (1000^2 * 0.044) / (3 * 8.314) = 700 K.

Using v_rms = sqrt(3RT/M), we rearrange to find T = (v_rms^2 * M) / (3R). Plugging in values gives T approximately 500 K.

Using the formula v_rms = sqrt((3RT)/M), we can rearrange to find T. Setting v_rms = 300 m/s and M = 28 g/mol, we find T = (M * v_rms^2)/(3R) = 600 K.

Using v_rms = sqrt(3RT/M), rearranging gives T = (v_rms^2 * M) / (3R). Substituting values gives T = 500 K.

Using v_rms = sqrt(3RT/M), we can rearrange to find T = (v_rms^2 * M) / (3R). Plugging in values gives T = (600^2 * 0.02) / (3 * 8.314) = 900 K.

At the equinox, the sun is directly overhead at the equator, which is at 0 degrees latitude.

During the summer solstice, the sun is directly overhead at the Tropic of Cancer, which is at 23.5°N latitude.

The sun does not set during the summer solstice at latitudes above the Arctic Circle (66.5°N).

The longest day occurs at the Arctic Circle during the summer solstice, where the sun does not set.

3 hours ahead means 3 * 15° = 45°. Therefore, 0° + 45° = 135°E.

3 hours ahead means 3 * 15 = 45 degrees East, so 0° + 45° = 135° East.

Each hour corresponds to 15 degrees. Therefore, 3 hours ahead means 3 * 15 = 45 degrees east of GMT, which is 45°E.

6 hours ahead corresponds to 6 * 15° = 90°. Therefore, 90°E is the correct answer.

150°E corresponds to UTC+6, as each 15° represents one hour.

The local time is the same as that of the Prime Meridian at 0° longitude.