Engineering Entrance MCQ & Objective Questions
Preparing for Engineering Entrance exams is crucial for aspiring engineers in India. Mastering MCQs and objective questions not only enhances your understanding of key concepts but also boosts your confidence during exams. Regular practice with these questions helps identify important topics and improves your overall exam preparation.
What You Will Practise Here
Fundamental concepts of Physics and Mathematics
Key formulas and their applications in problem-solving
Important definitions and theorems relevant to engineering
Diagrams and graphical representations for better understanding
Conceptual questions that challenge your critical thinking
Previous years' question papers and their analysis
Time management strategies while solving MCQs
Exam Relevance
The Engineering Entrance syllabus is integral to various examinations like CBSE, State Boards, NEET, and JEE. Questions often focus on core subjects such as Physics, Chemistry, and Mathematics, with formats varying from direct MCQs to application-based problems. Understanding the common question patterns can significantly enhance your performance and help you tackle the exams with ease.
Common Mistakes Students Make
Overlooking the importance of units and dimensions in calculations
Misinterpreting questions due to lack of careful reading
Neglecting to review basic concepts before attempting advanced problems
Rushing through practice questions without thorough understanding
FAQs
Question: What are the best ways to prepare for Engineering Entrance MCQs?Answer: Focus on understanding concepts, practice regularly with objective questions, and review previous years' papers.
Question: How can I improve my speed in solving MCQs?Answer: Regular practice, time-bound mock tests, and familiarizing yourself with common question types can help improve your speed.
Start your journey towards success by solving Engineering Entrance MCQ questions today! Test your understanding and build a strong foundation for your exams.
Q. A thin film of oil (n = 1.5) is on water (n = 1.33). What is the condition for destructive interference for light of wavelength 600 nm in air? (2022)
A.
2t = (m + 1/2)λ
B.
2t = mλ
C.
2t = (m + 1)λ
D.
2t = (m - 1/2)λ
Show solution
Solution
For destructive interference in a thin film with a higher refractive index below, the condition is 2t = (m + 1/2)λ/n, where n is the refractive index of the film.
Correct Answer:
A
— 2t = (m + 1/2)λ
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 10 seconds. What is the acceleration of the train?
A.
-2 m/s²
B.
-3 m/s²
C.
-4 m/s²
D.
-5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: a = (v - u) / t = (0 - 20) / 10 = -2 m/s².
Correct Answer:
C
— -4 m/s²
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the deceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².
Correct Answer:
C
— 4 m/s²
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the acceleration of the train?
A.
-4 m/s²
B.
-5 m/s²
C.
-6 m/s²
D.
-7 m/s²
Show solution
Solution
First convert speed to m/s: 72 km/h = 20 m/s. Using the formula: acceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².
Correct Answer:
B
— -5 m/s²
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Q. A transformer has 200 turns in the primary coil and 50 turns in the secondary coil. If the primary voltage is 240 V, what is the secondary voltage? (2023)
A.
60 V
B.
120 V
C.
240 V
D.
480 V
Show solution
Solution
Using the transformer equation Vp/Vs = Np/Ns, we find Vs = Vp × (Ns/Np) = 240 V × (50/200) = 60 V.
Correct Answer:
A
— 60 V
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Q. A transformer steps down voltage from 240 V to 120 V. If the primary coil has 100 turns, how many turns does the secondary coil have? (2023)
A.
50 turns
B.
100 turns
C.
200 turns
D.
300 turns
Show solution
Solution
Using the transformer equation Vp/Vs = Np/Ns, we have 240/120 = 100/Ns, giving Ns = 50 turns.
Correct Answer:
A
— 50 turns
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the period of the wave? (2019)
A.
0.00227 s
B.
0.005 s
C.
0.01 s
D.
0.001 s
Show solution
Solution
Period T = 1/f = 1/440 Hz ≈ 0.00227 s.
Correct Answer:
A
— 0.00227 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the time period of this sound wave? (2021)
A.
0.00227 s
B.
0.0045 s
C.
0.01 s
D.
0.005 s
Show solution
Solution
Time period (T) = 1/f = 1/440 Hz ≈ 0.00227 s.
Correct Answer:
A
— 0.00227 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the time period of the sound wave?
A.
0.00227 s
B.
0.005 s
C.
0.01 s
D.
0.02 s
Show solution
Solution
The time period T is the reciprocal of frequency f. Thus, T = 1/f = 1/440 ≈ 0.00227 s.
Correct Answer:
A
— 0.00227 s
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the wavelength of the sound in air (speed of sound = 340 m/s)? (2021)
A.
0.77 m
B.
0.85 m
C.
0.90 m
D.
1.00 m
Show solution
Solution
Wavelength λ is given by λ = v/f. Thus, λ = 340 m/s / 440 Hz ≈ 0.77 m.
Correct Answer:
A
— 0.77 m
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Q. A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the fork? (2020)
A.
0.00227 s
B.
0.0045 s
C.
0.01 s
D.
0.005 s
Show solution
Solution
Time period T = 1/f = 1/440 Hz ≈ 0.00227 s.
Correct Answer:
A
— 0.00227 s
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Q. A uniform rod of length L is pivoted at one end and released from rest. What is the angular speed when it reaches the vertical position? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Show solution
Solution
Using conservation of energy, potential energy converts to rotational kinetic energy. Angular speed ω = √(3g/L).
Correct Answer:
B
— √(2g/L)
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Q. A uniform rod of length L is pivoted at one end and released from rest. What is the angular speed just before it hits the ground? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
Show solution
Solution
Using conservation of energy, potential energy converts to rotational kinetic energy. Angular speed ω = √(3g/L).
Correct Answer:
B
— √(2g/L)
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Q. A vehicle travels 100 m in 5 seconds. What is its average speed?
A.
10 m/s
B.
15 m/s
C.
20 m/s
D.
25 m/s
Show solution
Solution
Average speed = total distance / total time = 100 m / 5 s = 20 m/s.
Correct Answer:
A
— 10 m/s
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Q. A vehicle travels with a uniform speed of 60 km/h. How far will it travel in 2 hours? (2023)
A.
80 km
B.
100 km
C.
120 km
D.
140 km
Show solution
Solution
Distance = speed * time = 60 km/h * 2 h = 120 km.
Correct Answer:
C
— 120 km
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Q. A wave has a frequency of 10 Hz and a wavelength of 2 m. What is its speed? (2023)
A.
5 m/s
B.
10 m/s
C.
20 m/s
D.
15 m/s
Show solution
Solution
The speed v of a wave is given by v = fλ. Therefore, v = 10 Hz * 2 m = 20 m/s.
Correct Answer:
C
— 20 m/s
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Q. A wave has a frequency of 10 Hz and a wavelength of 5 m. What is its speed? (2020)
A.
50 m/s
B.
10 m/s
C.
2 m/s
D.
5 m/s
Show solution
Solution
Speed (v) = frequency (f) × wavelength (λ) = 10 Hz × 5 m = 50 m/s.
Correct Answer:
A
— 50 m/s
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Q. A wave has a frequency of 50 Hz and a speed of 340 m/s. What is its wavelength? (2021)
A.
6.8 m
B.
7.0 m
C.
7.5 m
D.
8.0 m
Show solution
Solution
Wavelength λ is given by λ = v/f. Thus, λ = 340 m/s / 50 Hz = 6.8 m.
Correct Answer:
A
— 6.8 m
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Q. A wave has a frequency of 500 Hz and a wavelength of 0.6 m. What is the speed of the wave? (2022)
A.
300 m/s
B.
500 m/s
C.
600 m/s
D.
400 m/s
Show solution
Solution
Using the wave equation v = fλ, we find v = 500 Hz * 0.6 m = 300 m/s.
Correct Answer:
A
— 300 m/s
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Q. A wave has a frequency of 60 Hz and a wavelength of 1.5 m. What is its speed? (2022)
A.
90 m/s
B.
60 m/s
C.
40 m/s
D.
30 m/s
Show solution
Solution
Speed (v) = frequency (f) × wavelength (λ) = 60 Hz × 1.5 m = 90 m/s.
Correct Answer:
A
— 90 m/s
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Q. A wave has a frequency of 60 Hz and a wavelength of 3 m. What is its speed? (2016)
A.
180 m/s
B.
120 m/s
C.
60 m/s
D.
90 m/s
Show solution
Solution
Speed v = f × λ = 60 Hz × 3 m = 180 m/s.
Correct Answer:
A
— 180 m/s
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Q. A wave has a frequency of 60 Hz and a wavelength of 3 m. What is the speed of the wave?
A.
180 m/s
B.
120 m/s
C.
60 m/s
D.
30 m/s
Show solution
Solution
The speed v of a wave is given by v = fλ. Thus, v = 60 * 3 = 180 m/s.
Correct Answer:
B
— 120 m/s
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Q. A wave has a speed of 300 m/s and a frequency of 150 Hz. What is its wavelength? (2022)
A.
1 m
B.
2 m
C.
3 m
D.
4 m
Show solution
Solution
Wavelength λ can be calculated using the formula λ = v/f. Therefore, λ = 300 m/s / 150 Hz = 2 m.
Correct Answer:
B
— 2 m
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Q. A wave has a wavelength of 0.5 m and a frequency of 300 Hz. What is its speed? (2020)
A.
150 m/s
B.
300 m/s
C.
600 m/s
D.
1200 m/s
Show solution
Solution
Speed (v) = frequency (f) × wavelength (λ) = 300 Hz × 0.5 m = 150 m/s.
Correct Answer:
A
— 150 m/s
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Q. A wave on a string has a frequency of 10 Hz and a wavelength of 2 m. What is the speed of the wave? (2022)
A.
5 m/s
B.
10 m/s
C.
15 m/s
D.
20 m/s
Show solution
Solution
Wave speed v is given by v = fλ. Thus, v = 10 Hz * 2 m = 20 m/s.
Correct Answer:
B
— 10 m/s
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Q. A wave on a string has a frequency of 60 Hz and a wavelength of 0.5 m. What is the speed of the wave? (2021)
A.
30 m/s
B.
60 m/s
C.
120 m/s
D.
15 m/s
Show solution
Solution
Speed (v) = Frequency (f) × Wavelength (λ) = 60 Hz × 0.5 m = 30 m/s.
Correct Answer:
C
— 120 m/s
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Q. A wave on a string has a speed of 50 m/s and a wavelength of 2 m. What is its frequency? (2018)
A.
25 Hz
B.
50 Hz
C.
100 Hz
D.
75 Hz
Show solution
Solution
Frequency f = v/λ = 50 m/s / 2 m = 25 Hz.
Correct Answer:
A
— 25 Hz
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Q. A wave on a string is described by the equation y(x, t) = 0.05 sin(2π(0.1x - 5t)). What is the amplitude of the wave?
A.
0.01 m
B.
0.05 m
C.
0.1 m
D.
0.2 m
Show solution
Solution
The amplitude of the wave is the coefficient in front of the sine function. Here, the amplitude is 0.05 m.
Correct Answer:
B
— 0.05 m
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Q. A wave pulse travels along a string and reflects off a fixed end. What happens to the wave upon reflection? (2021)
A.
It inverts
B.
It remains unchanged
C.
It doubles in amplitude
D.
It disappears
Show solution
Solution
When a wave pulse reflects off a fixed end, it inverts due to the boundary condition at the fixed end.
Correct Answer:
A
— It inverts
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Q. A wave traveling along a string has a frequency of 50 Hz and a wavelength of 2 m. What is the speed of the wave? (2020)
A.
25 m/s
B.
50 m/s
C.
100 m/s
D.
75 m/s
Show solution
Solution
Speed (v) = frequency (f) × wavelength (λ) = 50 Hz × 2 m = 100 m/s.
Correct Answer:
C
— 100 m/s
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