Major Competitive Exams play a crucial role in shaping the academic and professional futures of students in India. These exams not only assess knowledge but also test problem-solving skills and time management. Practicing MCQs and objective questions is essential for scoring better, as they help in familiarizing students with the exam format and identifying important questions that frequently appear in tests.
What You Will Practise Here
Key concepts and theories related to major subjects
Important formulas and their applications
Definitions of critical terms and terminologies
Diagrams and illustrations to enhance understanding
Practice questions that mirror actual exam patterns
Strategies for solving objective questions efficiently
Time management techniques for competitive exams
Exam Relevance
The topics covered under Major Competitive Exams are integral to various examinations such as CBSE, State Boards, NEET, and JEE. Students can expect to encounter a mix of conceptual and application-based questions that require a solid understanding of the subjects. Common question patterns include multiple-choice questions that test both knowledge and analytical skills, making it essential to be well-prepared with practice MCQs.
Common Mistakes Students Make
Rushing through questions without reading them carefully
Overlooking the negative marking scheme in MCQs
Confusing similar concepts or terms
Neglecting to review previous years’ question papers
Failing to manage time effectively during the exam
FAQs
Question: How can I improve my performance in Major Competitive Exams? Answer: Regular practice of MCQs and understanding key concepts will significantly enhance your performance.
Question: What types of questions should I focus on for these exams? Answer: Concentrate on important Major Competitive Exams questions that frequently appear in past papers and mock tests.
Question: Are there specific strategies for tackling objective questions? Answer: Yes, practicing under timed conditions and reviewing mistakes can help develop effective strategies.
Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence for your upcoming exams. Remember, consistent practice is the key to mastering Major Competitive Exams!
Q. A solution has a density of 1.2 g/mL and contains 30 g of solute. What is the molarity if the molar mass of the solute is 60 g/mol?
A.
0.5 M
B.
1 M
C.
2 M
D.
1.5 M
Solution
Volume of solution = mass / density = 30 g / 1.2 g/mL = 25 mL = 0.025 L. Moles of solute = 30 g / 60 g/mol = 0.5 moles. Molarity = 0.5 moles / 0.025 L = 20 M.
Q. A solution is made by mixing 15 liters of a 30% acid solution with 5 liters of a 50% acid solution. What is the percentage of acid in the new solution?
Q. A solution is made by mixing 3 parts of solution A and 5 parts of solution B. If solution A contains 20% salt and solution B contains 10% salt, what is the percentage of salt in the final mixture?
Q. A solution is made by mixing 4 liters of a 20% acid solution with 6 liters of a 30% acid solution. What is the concentration of acid in the final mixture?
Q. A solution is made by mixing 5 liters of a 10% acid solution with 15 liters of a 20% acid solution. What is the concentration of acid in the final mixture?
Q. A solution is made by mixing two liquids in the ratio 3:4. If the total volume of the solution is 70 liters, how much of the second liquid is there?
A.
30 liters
B.
40 liters
C.
35 liters
D.
20 liters
Solution
In a 3:4 ratio, the total parts = 3 + 4 = 7. Second liquid = (4/7) * 70 = 40 liters.
Q. A solution is made by mixing two types of tea in the ratio 2:3. If the total weight of the mixture is 50 kg, how much of the first type of tea is there?
A.
20 kg
B.
30 kg
C.
25 kg
D.
15 kg
Solution
In a 2:3 ratio, total parts = 2 + 3 = 5. First type = (2/5) * 50 = 20 kg.
Q. A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
A.
20%
B.
15%
C.
25%
D.
10%
Solution
Mass percent = (mass of solute / (mass of solute + mass of solvent)) × 100 = (50 g / (50 g + 250 g)) × 100 = 20%.
Q. A solution is prepared by dissolving 58.5 g of NaCl in 1 L of water. What is the concentration in terms of molarity? (Molar mass of NaCl = 58.5 g/mol)
A.
1 M
B.
2 M
C.
0.5 M
D.
0.25 M
Solution
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
Q. A solution is prepared by dissolving 58.5 g of NaCl in enough water to make 1 L of solution. What is the molarity of the solution? (Molar mass of NaCl = 58.5 g/mol)
A.
1 M
B.
2 M
C.
0.5 M
D.
0.1 M
Solution
Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mole. Molarity = 1 mole / 1 L = 1 M.
