Major Competitive Exams

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Q. All teachers are educated. Some educated people are not teachers. Therefore, some people who are not teachers are educated. Is this conclusion valid? (2023)

A. Yes
B. No
C. Only if all educated people are teachers
D. Only if some teachers are educated

Solution

The conclusion is valid. The premises allow for the existence of educated people who are not teachers.

Correct Answer: A — Yes

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Q. Aman is facing north. He turns 90 degrees to his right and then 180 degrees to his left. In which direction is he now facing? (2023)

A. North
B. South
C. East
D. West

Solution

Aman starts facing North. Turning right 90 degrees, he faces East. Turning left 180 degrees, he faces West.

Correct Answer: B — South

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Q. An object is at rest on a frictionless surface. If a force of 50 N is applied, what will be its acceleration if the mass of the object is 10 kg? (2022)

A. 2 m/s²
B. 5 m/s²
C. 10 m/s²
D. 20 m/s²

Solution

Acceleration a = F/m = 50 N / 10 kg = 5 m/s².

Correct Answer: B — 5 m/s²

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Q. An object is dropped from a height of 20 m. How long will it take to reach the ground? (Take g = 10 m/s²)

A. 2 s
B. 4 s
C. 3 s
D. 5 s

Solution

Using the formula h = (1/2)gt², we have 20 = (1/2)(10)t², thus t² = 4, t = 2 s.

Correct Answer: B — 4 s

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Q. An object is dropped from a height of 20 m. What is its potential energy at the top? (2021)

A. 200 J
B. 400 J
C. 600 J
D. 800 J

Solution

Potential Energy (PE) = m * g * h = 5 kg * 9.8 m/s^2 * 20 m = 980 J (approximately 400 J for 1 kg)

Correct Answer: B — 400 J

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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Assume g = 10 m/s²)

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t². 80 = 0.5 * 10 * t². Solving gives t² = 16, so t = 4 s.

Correct Answer: B — 5 s

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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground?

A. 4 s
B. 5 s
C. 6 s
D. 8 s

Solution

Using the formula: h = 0.5 * g * t², where h = 80 m and g = 9.8 m/s². Solving for t gives t = sqrt(2h/g) = sqrt(2*80/9.8) ≈ 4.04 s, approximately 4 s.

Correct Answer: B — 5 s

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Q. An object is dropped from a height of 80 m. How long will it take to reach the ground? (Take g = 10 m/s²) (2023)

A. 4 s
B. 8 s
C. 10 s
D. 12 s

Solution

Using the formula: h = 0.5 * g * t^2. Rearranging gives t = sqrt(2h/g) = sqrt(2*80/10) = sqrt(16) = 4 s.

Correct Answer: B — 8 s

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Q. An object is in equilibrium under the action of three forces: 10 N, 15 N, and 20 N. What is the resultant force acting on the object? (2019)

A. 0 N
B. 5 N
C. 10 N
D. 15 N

Solution

In equilibrium, the resultant force is 0 N.

Correct Answer: A — 0 N

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Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?

A. 5 N
B. 10 N
C. 15 N
D. 0 N

Solution

In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.

Correct Answer: A — 5 N

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Q. An object is in equilibrium. What can be said about the net force acting on it?

A. It is zero
B. It is equal to its weight
C. It is equal to the applied force
D. It is maximum

Solution

For an object in equilibrium, the net force acting on it must be zero.

Correct Answer: A — It is zero

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Q. An object is in free fall. What is its acceleration?

A. 0 m/s²
B. 9.8 m/s²
C. 10 m/s²
D. 5 m/s²

Solution

In free fall, the only force acting on the object is gravity, so its acceleration is approximately 9.8 m/s².

Correct Answer: B — 9.8 m/s²

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Q. An object is lifted to a height of 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential Energy = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: B — 100 J

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Q. An object is lifted to a height of 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained? (g = 9.8 m/s²)

A. 49 J
B. 98 J
C. 245 J
D. 490 J

Solution

Potential Energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.

Correct Answer: B — 98 J

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Q. An object is lifted vertically 10 m against gravity. If the mass of the object is 5 kg, what is the work done against gravity?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Work done = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: B — 100 J

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Q. An object is lifted vertically 10 m. If the mass of the object is 5 kg, what is the gravitational potential energy gained?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Potential Energy (PE) = mgh = 5 kg * 9.8 m/s² * 10 m = 490 J.

Correct Answer: B — 100 J

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Q. An object is lifted vertically 3 m against gravity. If the mass of the object is 4 kg, what is the work done against gravity? (g = 9.8 m/s²)

A. 117.6 J
B. 39.2 J
C. 29.4 J
D. 19.6 J

Solution

Work done = mgh = 4 kg × 9.8 m/s² × 3 m = 117.6 J.

Correct Answer: A — 117.6 J

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Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 3 kg, what is the work done against gravity? (g = 9.8 m/s²)

A. 117.6 J
B. 29.4 J
C. 39.2 J
D. 78.4 J

Solution

Work done (W) = mgh = 3 kg × 9.8 m/s² × 4 m = 117.6 J.

Correct Answer: A — 117.6 J

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Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 10 kg, what is the work done against gravity? (g = 9.8 m/s²)

A. 39.2 J
B. 78.4 J
C. 98 J
D. 196 J

Solution

Work done (W) = mgh = 10 kg × 9.8 m/s² × 4 m = 392 J.

Correct Answer: B — 78.4 J

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Q. An object is lifted vertically 4 m against gravity. If the mass of the object is 10 kg, what is the work done against gravity? (2021)

A. 40 J
B. 80 J
C. 100 J
D. 200 J

Solution

Work Done = m * g * h = 10 kg * 9.8 m/s² * 4 m = 392 J (approx. 400 J).

Correct Answer: B — 80 J

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Q. An object is lifted vertically 4 m. If the weight of the object is 50 N, how much work is done against gravity?

A. 100 J
B. 200 J
C. 150 J
D. 50 J

Solution

Work done (W) = Force (F) × Distance (d) = 50 N × 4 m = 200 J.

Correct Answer: B — 200 J

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Q. An object is lifted vertically to a height of 10 m. If the mass of the object is 5 kg, what is the work done against gravity?

A. 50 J
B. 100 J
C. 150 J
D. 200 J

Solution

Work done = mass × g × height = 5 kg × 9.8 m/s² × 10 m = 490 J.

Correct Answer: B — 100 J

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Q. An object is moving in a circular path with a constant speed. What can be said about the work done by the centripetal force?

A. Positive work
B. Negative work
C. Zero work
D. Depends on speed

Solution

Centripetal force does no work as it acts perpendicular to the direction of motion.

Correct Answer: C — Zero work

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Q. An object is moving in a circular path with a constant speed. What type of energy is primarily involved?

A. Kinetic Energy
B. Potential Energy
C. Mechanical Energy
D. Thermal Energy

Solution

The object has Kinetic Energy due to its motion in the circular path.

Correct Answer: A — Kinetic Energy

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Q. An object is moving in a circular path with a radius of 10 m and a speed of 5 m/s. What is the net force acting on the object if its mass is 2 kg?

A. 1 N
B. 2 N
C. 5 N
D. 10 N

Solution

Centripetal force (F_c) = mv²/r = 2 kg * (5 m/s)² / (10 m) = 5 N.

Correct Answer: D — 10 N

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Q. An object is moving in a circular path with a radius of 10 m at a speed of 5 m/s. What is the period of the motion?

A. 2π s
B. 4π s
C. 10 s
D. 20 s

Solution

Period (T) = 2πr/v = 2π(10)/5 = 4π s.

Correct Answer: A — 2π s

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Q. An object is moving in a circular path with a radius of 3 m and an angular speed of 2 rad/s. What is the linear speed of the object?

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

Linear speed (v) = rω = 3 m * 2 rad/s = 6 m/s.

Correct Answer: B — 6 m/s

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Q. An object is moving with a speed of 15 m/s and has a mass of 3 kg. What is its kinetic energy?

A. 67.5 J
B. 45 J
C. 90 J
D. 135 J

Solution

Kinetic Energy (KE) = 0.5 × m × v² = 0.5 × 3 kg × (15 m/s)² = 0.5 × 3 × 225 = 337.5 J.

Correct Answer: C — 90 J

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Q. An object is moving with a velocity of 10 m/s. What is its kinetic energy if its mass is 2 kg? (2022)

A. 10 J
B. 20 J
C. 30 J
D. 40 J

Solution

Kinetic Energy = (1/2)mv² = (1/2) × 2 kg × (10 m/s)² = 100 J

Correct Answer: B — 20 J

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Q. An object is placed 10 cm from a convex lens with a focal length of 5 cm. What is the nature of the image formed? (2022)

A. Real and inverted
B. Virtual and erect
C. Real and erect
D. Virtual and inverted

Solution

Since the object distance is less than the focal length, the image formed is virtual and erect.

Correct Answer: B — Virtual and erect

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Major Competitive Exams

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