Undergraduate MCQ & Objective Questions
The undergraduate level is a crucial phase in a student's academic journey, especially for those preparing for school and competitive exams. Mastering this stage can significantly enhance your understanding and retention of key concepts. Practicing MCQs and objective questions is essential, as it not only helps in reinforcing knowledge but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Fundamental concepts in Mathematics and Science
Key definitions and theories across various subjects
Important formulas and their applications
Diagrams and graphical representations
Critical thinking and problem-solving techniques
Subject-specific MCQs designed for competitive exams
Revision of essential topics for better retention
Exam Relevance
Undergraduate topics are integral to various examinations such as CBSE, State Boards, NEET, and JEE. These subjects often feature a mix of conceptual and application-based questions. Common patterns include multiple-choice questions that assess both theoretical knowledge and practical application, making it vital for students to be well-versed in undergraduate concepts.
Common Mistakes Students Make
Overlooking the importance of understanding concepts rather than rote memorization
Misinterpreting questions due to lack of careful reading
Neglecting to practice numerical problems that require application of formulas
Failing to review mistakes made in previous practice tests
FAQs
Question: What are some effective strategies for solving undergraduate MCQ questions?Answer: Focus on understanding the concepts, practice regularly, and review your answers to learn from mistakes.
Question: How can I improve my speed in answering objective questions?Answer: Time yourself while practicing and gradually increase the number of questions you attempt in a set time.
Start your journey towards mastering undergraduate subjects today! Solve practice MCQs and test your understanding to ensure you are well-prepared for your exams. Your success is just a question away!
Q. What is the particular solution of dy/dx = 4y with the initial condition y(0) = 2?
A.
y = 2e^(4x)
B.
y = e^(4x)
C.
y = 4e^(4x)
D.
y = 2e^(x)
Show solution
Solution
The general solution is y = Ce^(4x). Using the initial condition y(0) = 2, we find C = 2, thus y = 2e^(4x).
Correct Answer:
A
— y = 2e^(4x)
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Q. What is the path difference for the first minimum in a single-slit diffraction pattern? (2021)
A.
λ/2
B.
λ
C.
3λ/2
D.
λ/4
Show solution
Solution
The path difference for the first minimum in single-slit diffraction is λ/2.
Correct Answer:
A
— λ/2
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Q. What is the peak voltage of an AC source if its RMS voltage is 220 V? (2021)
A.
311 V
B.
220 V
C.
155 V
D.
440 V
Show solution
Solution
The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.
Correct Answer:
A
— 311 V
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Q. What is the peak voltage of an AC supply if its RMS voltage is 220 V? (2021)
A.
311 V
B.
220 V
C.
155 V
D.
440 V
Show solution
Solution
The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.
Correct Answer:
A
— 311 V
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Q. What is the percentage by mass of a solution containing 15 grams of solute in 85 grams of solvent? (2021)
A.
15%
B.
17.65%
C.
20%
D.
25%
Show solution
Solution
Percentage by mass = (mass of solute / total mass) × 100 = (15 g / (15 g + 85 g)) × 100 = 17.65%.
Correct Answer:
B
— 17.65%
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Q. What is the percentage concentration of a solution containing 15 g of solute in 150 g of solution? (2023)
A.
10%
B.
15%
C.
20%
D.
25%
Show solution
Solution
Percentage concentration = (mass of solute / mass of solution) × 100 = (15 g / 150 g) × 100 = 10%
Correct Answer:
B
— 15%
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Q. What is the percentage concentration of a solution containing 20 g of solute in 200 g of solution? (2021)
A.
10%
B.
20%
C.
5%
D.
15%
Show solution
Solution
Percentage concentration = (mass of solute / mass of solution) × 100 = (20 g / 200 g) × 100 = 10%.
Correct Answer:
A
— 10%
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Q. What is the percentage error if the measured value is 10.0 and the true value is 9.5? (2021)
A.
5.26%
B.
4.76%
C.
2.5%
D.
10%
Show solution
Solution
Percentage error = (|Measured - True| / True) × 100 = (|10.0 - 9.5| / 9.5) × 100 = 5.26%.
Correct Answer:
B
— 4.76%
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Q. What is the percentage error if the measured value is 20 and the true value is 25? (2021)
A.
20%
B.
25%
C.
5%
D.
10%
Show solution
Solution
Percentage error is calculated as (|True Value - Measured Value| / True Value) * 100 = (|25 - 20| / 25) * 100 = 20%.
Correct Answer:
D
— 10%
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Q. What is the percentage error if the measured value is 20.0 and the true value is 19.5? (2021)
A.
2.56%
B.
1.25%
C.
3.33%
D.
5.00%
Show solution
Solution
Percentage error = (|Measured - True| / True) × 100 = (|20.0 - 19.5| / 19.5) × 100 ≈ 2.56%.
Correct Answer:
A
— 2.56%
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Q. What is the percentage error if the true value is 50 and the measured value is 48? (2022)
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Solution
Percentage error = |(True value - Measured value) / True value| * 100 = |(50 - 48) / 50| * 100 = 4%.
Correct Answer:
A
— 4%
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Q. What is the period number of Argon? (2020)
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Solution
Argon is located in Period 3 of the periodic table.
Correct Answer:
C
— 4
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Q. What is the period number of Lithium in the periodic table? (2022)
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Solution
Lithium is located in period 2 of the periodic table.
Correct Answer:
B
— 2
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Q. What is the period number of Lithium? (2016) 2016
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Solution
Lithium is located in period 2 of the periodic table.
Correct Answer:
B
— 2
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Q. What is the period number of Sodium in the periodic table? (2017)
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Solution
Sodium is in period 3 of the periodic table.
Correct Answer:
C
— 3
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Q. What is the pH of a 0.001 M acetic acid solution (Ka = 1.8 x 10^-5)?
A.
2.87
B.
3.87
C.
4.87
D.
5.87
Show solution
Solution
Using the formula for weak acids, pH = 0.5(pKa - logC) = 0.5(4.74 - log(0.001)) = 3.87.
Correct Answer:
B
— 3.87
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Q. What is the pH of a 0.001 M solution of hydrochloric acid?
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Solution
pH = -log(0.001) = 3.
Correct Answer:
A
— 3
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Q. What is the pH of a 0.01 M HCl solution? (2021) 2021
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Solution
For a strong acid like HCl, pH = -log[H+] = -log(0.01) = 2.
Correct Answer:
A
— 1
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Q. What is the pH of a 0.01 M solution of Na2CO3?
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Solution
Na2CO3 is a basic salt, pH is approximately 11.5.
Correct Answer:
C
— 12
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Q. What is the pH of a 0.01 M solution of NaOH?
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Solution
pOH = -log(0.01) = 2; pH = 14 - pOH = 14 - 2 = 12.
Correct Answer:
B
— 13
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Q. What is the pH of a 0.01 M solution of phosphoric acid (H3PO4)?
A.
1.0
B.
2.0
C.
3.0
D.
4.0
Show solution
Solution
H3PO4 is a triprotic acid; for a dilute solution, the first dissociation dominates, giving pH ≈ 2.
Correct Answer:
B
— 2.0
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Q. What is the pH of a 0.05 M acetic acid solution (Ka = 1.8 x 10^-5)? (2023)
A.
2.9
B.
3.1
C.
4.0
D.
4.7
Show solution
Solution
Using the formula for weak acids, pH = 0.5(pKa - log[C]) where pKa = -log(1.8 x 10^-5) ≈ 4.74. pH = 0.5(4.74 - log(0.05)) ≈ 4.7.
Correct Answer:
D
— 4.7
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Q. What is the pH of a 0.05 M solution of NaCl?
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Solution
NaCl is a neutral salt, so the pH remains 7.
Correct Answer:
A
— 7
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Q. What is the pH of a 0.1 M solution of ammonium chloride (NH4Cl)? (2019) 2019
A.
5.10
B.
4.75
C.
6.00
D.
7.00
Show solution
Solution
NH4Cl is a salt of a weak base and strong acid, pH < 7. Calculate using hydrolysis: pH ≈ 4.75.
Correct Answer:
B
— 4.75
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Q. What is the pH of a 0.1 M solution of K2CO3?
A.
9.0
B.
10.0
C.
11.0
D.
12.0
Show solution
Solution
K2CO3 is a salt of a weak acid (H2CO3) and strong base (KOH), resulting in a basic solution with pH around 10.
Correct Answer:
B
— 10.0
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Q. What is the pH of a 0.1 M solution of K2SO4? (2023)
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Solution
K2SO4 is a neutral salt formed from a strong acid (H2SO4) and a strong base (KOH). Therefore, the pH of the solution is 7.
Correct Answer:
A
— 7
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Q. What is the pH of a 0.1 M solution of NH4Cl?
Show solution
Solution
NH4Cl is an acidic salt, pH is approximately 5.1.
Correct Answer:
B
— 6
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Q. What is the pH of a 0.1 M solution of sodium acetate (Ka for acetic acid = 1.8 x 10^-5)?
A.
4.75
B.
5.25
C.
9.25
D.
10.25
Show solution
Solution
Using the formula for salt of weak acid, pH = 14 + 0.5(pKa + logC) = 14 + 0.5(4.74 + log(0.1)) = 9.25.
Correct Answer:
C
— 9.25
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Q. What is the pH of a 0.1 M solution of sodium bicarbonate (NaHCO3)? (2022) 2022
A.
8.00
B.
9.00
C.
7.00
D.
6.00
Show solution
Solution
NaHCO3 is a weak base, pH ≈ 8.00 due to its bicarbonate ion acting as a weak base.
Correct Answer:
A
— 8.00
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Q. What is the pH of a 0.1 M solution of sulfuric acid (H2SO4)?
Show solution
Solution
H2SO4 is a strong acid; it dissociates completely, so [H+] = 0.1 M; pH = -log(0.1) = 1.
Correct Answer:
B
— 2
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