The focal length (f) of a mirror is given by f = R/2. For a convex mirror, R is positive, so f = 20 cm / 2 = 10 cm.

According to Ohm's Law, if the resistance (R) is doubled and the voltage (V) remains constant, the current (I) will be halved (I = V/R).

Shear modulus (G) = Shear stress / Shear strain, thus it is 80 GPa.

The peak voltage (V_peak) is calculated as V_peak = V_rms × √2 = 100 V × √2 ≈ 141.42 V.

According to Ohm's law, if voltage increases and resistance remains constant, current will also increase proportionally.

Inductive reactance (X_L) is given by X_L = V/I. Here, X_L = 100 V / 2 A = 50 Ω.

Inductive reactance (X_L) can be calculated using the formula V = I × X_L. Rearranging gives X_L = V/I = 100 V / 5 A = 20 Ω.

The electric fields due to both charges at the midpoint cancel each other out, resulting in a net electric field of 0 N/C.

The electric fields due to both charges at the midpoint will cancel each other, resulting in a net electric field of 0 N/C.

Total resistance R = 4Ω + 12Ω = 16Ω. Voltage V = I * R = 2A * 16Ω = 32V.

Using the formula for parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/6 = 5/12, R_eq = 12/5 = 2.4Ω.

In series, R_total = R1 + R2 = 5Ω + 10Ω = 15Ω.

Capacitance (C) is defined as C = Q/V. If the charge (Q) is doubled while the voltage (V) remains constant, the capacitance also doubles.

Increasing the plate area while keeping the distance constant increases the capacitance, as capacitance is directly proportional to the area of the plates.

Power P = V^2/R = 5^2/10 = 25/10 = 2.5W.

Total resistance R = 10Ω + 5Ω = 15Ω. Voltage V = I * R = 2A * 15Ω = 30V.

Total resistance R = 4Ω + 4Ω = 8Ω. Current I = V/R = 12V/8Ω = 1.5A.

The voltage drop across the resistor is equal to the battery voltage, which is 15V.

The total resistance is 15Ω. The current I = V/R = 15V/15Ω = 1A. Voltage drop across 10Ω = I * R = 1A * 10Ω = 10V.

Power (P) can be calculated using P = V^2 / R. Here, P = 24V^2 / 6Ω = 96W.

Power P = V^2/R = 24^2/8 = 576/8 = 72 W.

Total resistance R_total = 3Ω + 6Ω = 9Ω. Current I = V/R_total = 9V/9Ω = 1A. Voltage across 6Ω = I * R = 1A * 6Ω = 6V.

Total resistance R = 3Ω + 6Ω = 9Ω. Current I = V/R = 9V/9Ω = 1A.

Using Ohm's Law, R = V/I = 24V / 6A = 4Ω.

In a circuit with an inductor, the current increases gradually due to the inductor's opposition to changes in current.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

According to Ohm's law, I = V/R. If R is doubled, I will be halved.

Using Ohm's Law, R = V / I = 24V / 3A = 8Ω.

According to Ohm's law, if V is tripled, I will also triple.