Q. What is the electric field at a distance r from an infinitely long line charge with linear charge density λ?
A.
λ/2πε₀r
B.
λ/4πε₀r²
C.
λ/ε₀r
D.
λ/2ε₀r²
Show solution
Solution
The electric field due to an infinite line charge is given by E = λ/2πε₀r.
Correct Answer:
A
— λ/2πε₀r
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Q. What is the electric field at a distance r from an infinitely long line of charge with linear charge density λ?
A.
λ/(2πε₀r)
B.
λ/(4πε₀r²)
C.
λ/(2πε₀r²)
D.
0
Show solution
Solution
The electric field due to an infinitely long line of charge is given by E = λ/(2πε₀r), directed radially outward from the line.
Correct Answer:
A
— λ/(2πε₀r)
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Q. What is the electric field at a point due to a positive charge?
A.
Directed towards the charge
B.
Directed away from the charge
C.
Zero
D.
Depends on the distance from the charge
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Solution
The electric field due to a positive charge is directed away from the charge.
Correct Answer:
B
— Directed away from the charge
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Q. What is the electric field at a point just outside a charged conductor?
A.
0
B.
σ/ε₀
C.
σ/2ε₀
D.
σ/4ε₀
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Solution
The electric field just outside a charged conductor is given by E = σ/ε₀, where σ is the surface charge density.
Correct Answer:
B
— σ/ε₀
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Q. What is the electric field at a point midway between two equal and opposite charges?
A.
Zero
B.
Maximum
C.
Minimum
D.
Depends on distance
Show solution
Solution
The electric fields due to both charges cancel each other out at the midpoint, resulting in zero electric field.
Correct Answer:
A
— Zero
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Q. What is the electric field at a point on the axis of a dipole at a distance d from the center of the dipole?
A.
0
B.
p/(4πε₀d²)
C.
p/(2πε₀d²)
D.
p/(4πε₀d³)
Show solution
Solution
The electric field along the axis of a dipole at a distance d is given by E = (1/(4πε₀)) * (2p/d³), where p is the dipole moment.
Correct Answer:
D
— p/(4πε₀d³)
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Q. What is the electric field at a point outside a uniformly charged sphere of radius R and total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a point outside a uniformly charged sphere, the electric field behaves as if all the charge were concentrated at the center, so E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric field due to a point charge at a distance r?
A.
k * q / r^2
B.
k * q / r
C.
k * q * r
D.
k * q * r^2
Show solution
Solution
The electric field E due to a point charge q at a distance r is given by E = k * q / r^2, where k is Coulomb's constant.
Correct Answer:
A
— k * q / r^2
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Q. What is the electric field due to a point charge of +10μC at a distance of 0.2m?
A.
22500 N/C
B.
45000 N/C
C.
50000 N/C
D.
75000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (0.2 m)² = 225000 N/C.
Correct Answer:
C
— 50000 N/C
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Q. What is the electric field due to a point charge of +1μC at a distance of 0.1m?
A.
9000 N/C
B.
900 N/C
C.
90 N/C
D.
9 N/C
Show solution
Solution
Electric field E = k * |q| / r^2 = (9 × 10^9) * (1 × 10^-6) / (0.1)^2 = 9000 N/C.
Correct Answer:
A
— 9000 N/C
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Q. What is the electric field due to a point charge of +1μC at a distance of 1m?
A.
9 × 10^9 N/C
B.
1 × 10^6 N/C
C.
9 × 10^6 N/C
D.
1 × 10^9 N/C
Show solution
Solution
Electric field E = k * |q| / r^2 = (9 × 10^9) * (1 × 10^-6) / (1)^2 = 9 × 10^6 N/C.
Correct Answer:
C
— 9 × 10^6 N/C
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Q. What is the electric field due to a point charge of +4μC at a distance of 0.1m?
A.
36000 N/C
B.
40000 N/C
C.
44000 N/C
D.
48000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (4 × 10^-6 C) / (0.1 m)² = 36000 N/C.
Correct Answer:
B
— 40000 N/C
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Q. What is the electric field due to a point charge of +4μC at a distance of 0.2m?
A.
4500 N/C
B.
9000 N/C
C.
18000 N/C
D.
36000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (4 × 10^-6) / (0.2)^2 = 9000 N/C.
Correct Answer:
B
— 9000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1 m?
A.
4500 N/C
B.
5000 N/C
C.
5500 N/C
D.
6000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 4500 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.1m?
A.
4500 N/C
B.
5000 N/C
C.
45000 N/C
D.
50000 N/C
Show solution
Solution
Electric field E = k * |q| / r² = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (0.1 m)² = 45000 N/C.
Correct Answer:
C
— 45000 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.2m?
A.
11250 N/C
B.
4500 N/C
C.
2250 N/C
D.
5625 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.2)^2 = 11250 N/C.
Correct Answer:
A
— 11250 N/C
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Q. What is the electric field due to a point charge of +5μC at a distance of 0.3m? (2000)
A.
1500 N/C
B.
5000 N/C
C.
1000 N/C
D.
2000 N/C
Show solution
Solution
E = k * |q| / r^2 = (9 × 10^9) * (5 × 10^-6) / (0.3)^2 = 5000 N/C.
Correct Answer:
B
— 5000 N/C
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Q. What is the electric field due to a uniformly charged infinite plane sheet with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
2σ/ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet is E = σ/2ε₀ on both sides, thus total E = σ/ε₀.
Correct Answer:
C
— 2σ/ε₀
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Q. What is the electric field due to a uniformly charged infinite plane sheet?
A.
0
B.
σ/2ε₀
C.
σ/ε₀
D.
σ/4ε₀
Show solution
Solution
According to Gauss's law, the electric field due to an infinite plane sheet with surface charge density σ is E = σ/2ε₀, directed away from the sheet.
Correct Answer:
B
— σ/2ε₀
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Q. What is the electric field due to a uniformly charged line of charge with linear charge density λ at a distance r from the line?
A.
λ/(2πε₀r)
B.
λ/(4πε₀r²)
C.
2λ/(πε₀r)
D.
λ/(ε₀r)
Show solution
Solution
Using Gauss's law, the electric field due to a uniformly charged line of charge is E = λ/(2πε₀r).
Correct Answer:
A
— λ/(2πε₀r)
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Q. What is the electric field due to an infinite plane sheet of charge with surface charge density σ?
A.
σ/2ε₀
B.
σ/ε₀
C.
σ/4ε₀
D.
0
Show solution
Solution
The electric field due to an infinite plane sheet of charge is given by E = σ/2ε₀, directed away from the sheet if the charge is positive.
Correct Answer:
A
— σ/2ε₀
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Q. What is the electric field inside a charged conductor in electrostatic equilibrium?
A.
Zero
B.
Constant
C.
Varies with distance
D.
Depends on charge density
Show solution
Solution
Inside a charged conductor in electrostatic equilibrium, the electric field is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged hollow sphere?
A.
Zero
B.
Uniform and equal to the surface field
C.
Varies linearly with distance from the center
D.
Depends on the charge outside the sphere
Show solution
Solution
According to Gauss's law, the electric field inside a uniformly charged hollow sphere is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field inside a uniformly charged spherical shell?
A.
Zero
B.
Uniform
C.
Varies linearly
D.
Depends on the charge outside
Show solution
Solution
The electric field inside a uniformly charged spherical shell is zero.
Correct Answer:
A
— Zero
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Q. What is the electric field outside a uniformly charged sphere of radius R with total charge Q?
A.
0
B.
Q/(4πε₀R²)
C.
Q/(4πε₀R)
D.
Q/(2πε₀R²)
Show solution
Solution
For a uniformly charged sphere, outside the sphere, the electric field behaves as if all the charge were concentrated at the center, E = Q/(4πε₀R²).
Correct Answer:
B
— Q/(4πε₀R²)
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Q. What is the electric flux through a closed surface surrounding a charge of -3Q?
A.
-3Q/ε₀
B.
3Q/ε₀
C.
0
D.
-6Q/ε₀
Show solution
Solution
According to Gauss's law, the electric flux through a closed surface is Φ = Q_enc/ε₀. Here, Q_enc = -3Q, so Φ = -3Q/ε₀.
Correct Answer:
A
— -3Q/ε₀
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Q. What is the electric flux through a closed surface surrounding a charge Q?
A.
0
B.
Q/ε₀
C.
Q/2ε₀
D.
Q/4ε₀
Show solution
Solution
According to Gauss's law, the electric flux Φ through a closed surface is given by Φ = Q/ε₀.
Correct Answer:
B
— Q/ε₀
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Q. What is the electric flux through a closed surface that encloses no charge?
A.
0
B.
Q/ε₀
C.
Q
D.
4πQ/ε₀
Show solution
Solution
According to Gauss's law, if there is no charge enclosed, the electric flux through the surface is zero.
Correct Answer:
A
— 0
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Q. What is the electric potential at a distance of 3 m from a charge of 10 μC?
A.
3000 V
B.
9000 V
C.
6000 V
D.
1000 V
Show solution
Solution
V = k * q / r = (9 × 10^9 N m²/C²) * (10 × 10^-6 C) / (3 m) = 30000 V / 3 = 9000 V.
Correct Answer:
B
— 9000 V
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Q. What is the electric potential at a distance of 4 m from a charge of 8 μC? (2000)
A.
4500 V
B.
1800 V
C.
2000 V
D.
None of the above
Show solution
Solution
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (8 × 10^-6 C) / (4 m) = 1800 V.
Correct Answer:
B
— 1800 V
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Showing 271 to 300 of 363 (13 Pages)
Electrostatics MCQ & Objective Questions
Electrostatics is a crucial topic in physics that deals with the study of electric charges at rest. Understanding electrostatics is essential for students preparing for school exams and competitive tests, as it forms the foundation for many advanced concepts in physics. Practicing MCQs and objective questions on electrostatics not only enhances conceptual clarity but also boosts your confidence in tackling important questions during exams.
What You Will Practise Here
Fundamental concepts of electric charge and its properties
Understanding Coulomb's Law and its applications
Electric field and electric potential: definitions and calculations
Capacitance and capacitors: types and formulas
Gauss's Law and its significance in electrostatics
Concept of electric dipoles and their behavior in electric fields
Key diagrams and graphical representations related to electrostatics
Exam Relevance
Electrostatics is a significant topic in various exams, including CBSE, State Boards, NEET, and JEE. It frequently appears in the form of conceptual questions, numerical problems, and application-based scenarios. Students can expect to encounter questions that require them to apply Coulomb's Law, calculate electric fields, and analyze capacitor circuits. Familiarity with common question patterns will greatly aid in effective exam preparation.
Common Mistakes Students Make
Confusing the concepts of electric field and electric potential
Misapplying Coulomb's Law in multi-charge systems
Neglecting the direction of electric field lines in problem-solving
Overlooking the significance of units and dimensions in calculations
Failing to understand the behavior of capacitors in series and parallel
FAQs
Question: What is the difference between electric field and electric potential?Answer: The electric field is a vector quantity that represents the force experienced by a unit positive charge, while electric potential is a scalar quantity that indicates the potential energy per unit charge at a point in an electric field.
Question: How do capacitors store energy?Answer: Capacitors store energy in the form of an electric field created between their plates when a voltage is applied across them.
Now is the time to strengthen your understanding of electrostatics! Dive into our practice MCQs and test your knowledge on this vital topic. The more you practice, the better prepared you will be for your exams!
