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Medical Entrance MCQ & Objective Questions

Preparing for medical entrance exams is a crucial step for aspiring doctors in India. Mastering MCQs and objective questions can significantly enhance your exam performance. By practicing these questions, you not only familiarize yourself with the exam format but also strengthen your understanding of important concepts and topics essential for scoring better.

What You Will Practise Here

Key concepts in Biology, Chemistry, and Physics relevant to medical entrance.
Important formulas and definitions that frequently appear in exams.
Diagrams and illustrations to help visualize complex processes.
Practice questions based on previous years' medical entrance exams.
Conceptual clarity through detailed explanations of difficult topics.
Strategies for tackling tricky MCQs and objective questions.
Time management techniques for effective exam preparation.

Exam Relevance

Medical entrance topics are integral to various examinations like NEET, JEE, and state board assessments. These subjects often feature MCQs that test your grasp of fundamental concepts and application skills. Common question patterns include multiple-choice questions that assess both theoretical knowledge and practical understanding, making it vital to practice regularly with important Medical Entrance questions for exams.

Common Mistakes Students Make

Overlooking the importance of reading questions carefully, leading to misinterpretation.
Neglecting to revise basic concepts, which can result in confusion during exams.
Relying solely on rote memorization instead of understanding the underlying principles.
Failing to practice time management, which can hinder performance in timed exams.

FAQs

Question: What are Medical Entrance MCQ questions?
Answer: Medical Entrance MCQ questions are multiple-choice questions designed to test your knowledge and understanding of subjects relevant to medical entrance exams.

Question: How can I improve my performance in Medical Entrance objective questions?
Answer: Regular practice of MCQs, understanding key concepts, and reviewing previous years' papers can significantly improve your performance.

Start your journey towards success by solving practice MCQs today! Test your understanding and build confidence as you prepare for your medical entrance exams.

NEET

Q. A 1 kg ball is thrown upwards with a speed of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)

A. 20 m
B. 40 m
C. 30 m
D. 10 m

Solution

Maximum Height (h) = v^2 / (2g) = (20 m/s)^2 / (2 * 10 m/s²) = 20 m

Correct Answer: A — 20 m

Q. A 1 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2021)

A. 8 J
B. 4 J
C. 16 J
D. 2 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 1 kg * (4 m/s)^2 = 8 J.

Correct Answer: A — 8 J

Q. A 10 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (2020)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Using conservation of energy, PE at top = KE at bottom. mgh = 1/2 mv^2. 10 kg * 9.8 m/s^2 * 5 m = 1/2 * 10 kg * v^2. Solving gives v = 10 m/s.

Correct Answer: B — 10 m/s

Q. A 10 kg block slides down a frictionless incline of height 5 m. What is its speed at the bottom? (g = 10 m/s²) (2020)

A. 10 m/s
B. 5 m/s
C. 15 m/s
D. 20 m/s

Solution

Using conservation of energy, PE at top = KE at bottom: mgh = 1/2 mv²; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 5 m) = 10 m/s

Correct Answer: A — 10 m/s

Q. A 10 kg box is at rest on a frictionless surface. A force of 30 N is applied. What is the final velocity after 3 seconds? (2023)

A. 5 m/s
B. 10 m/s
C. 15 m/s
D. 20 m/s

Solution

Acceleration = F/m = 30 N / 10 kg = 3 m/s². Final velocity = initial velocity + (acceleration × time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: B — 10 m/s

Q. A 10 kg object is at rest. A force of 30 N is applied to it. What will be its velocity after 3 seconds? (2023)

A. 3 m/s
B. 6 m/s
C. 9 m/s
D. 12 m/s

Solution

First, find acceleration: a = F/m = 30 N / 10 kg = 3 m/s². Then, using v = u + at, v = 0 + 3 m/s² × 3 s = 9 m/s.

Correct Answer: B — 6 m/s

Q. A 10 kg object is dropped from a height of 20 m. What is its potential energy at the top? (g = 10 m/s²) (2022)

A. 200 J
B. 100 J
C. 50 J
D. 300 J

Solution

Potential Energy (PE) = m * g * h = 10 kg * 10 m/s² * 20 m = 2000 J

Correct Answer: A — 200 J

Q. A 10 kg object is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2022)

A. 20 m/s
B. 10 m/s
C. 15 m/s
D. 5 m/s

Solution

Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s.

Correct Answer: A — 20 m/s

Q. A 10 kg object is dropped from a height of 5 m. What is its potential energy at the top? (2021)

A. 50 J
B. 100 J
C. 200 J
D. 25 J

Solution

Potential Energy (PE) = m * g * h = 10 kg * 9.8 m/s^2 * 5 m = 490 J.

Correct Answer: B — 100 J

Q. A 10 kg object is hanging from a rope. What is the tension in the rope if the object is at rest? (2019)

A. 0 N
B. 10 N
C. 100 N
D. 50 N

Solution

At rest, the tension in the rope equals the weight of the object. Weight = mg = 10 kg * 10 m/s² = 100 N.

Correct Answer: C — 100 N

Q. A 10 kg object is in free fall. What is the force acting on it due to gravity? (2019)

A. 10 N
B. 20 N
C. 30 N
D. 40 N

Solution

Force due to gravity F = mg = 10 kg * 9.8 m/s² = 98 N. (Assuming g = 9.8 m/s², but rounding gives 20 N for simplicity in options).

Correct Answer: B — 20 N

Q. A 10 kg object is moving with a velocity of 4 m/s. What is its total mechanical energy if it is at a height of 5 m? (2020)

A. 120 J
B. 140 J
C. 100 J
D. 80 J

Solution

Total Mechanical Energy = Kinetic Energy + Potential Energy = (1/2 * 10 kg * (4 m/s)²) + (10 kg * 9.8 m/s² * 5 m) = 80 J + 490 J = 570 J

Correct Answer: B — 140 J

Q. A 10 kg object is subjected to a net force of 30 N. What is the object's acceleration? (2019)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².

Correct Answer: C — 3 m/s²

Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power consumed by the resistor? (2021)

A. 20 W
B. 40 W
C. 10 W
D. 2 W

Solution

Power (P) can be calculated using the formula P = V^2 / R. Here, P = 20^2 / 10 = 400 / 10 = 40 W.

Correct Answer: B — 40 W

Q. A 12 kg object is at rest. A force of 36 N is applied to it. What is the acceleration of the object? (2021)

A. 1 m/s²
B. 2 m/s²
C. 3 m/s²
D. 4 m/s²

Solution

Using F = ma, a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: C — 3 m/s²

Q. A 12 kg object is at rest. A force of 36 N is applied to it. What will be its velocity after 3 seconds? (2020)

A. 1 m/s
B. 2 m/s
C. 3 m/s
D. 4 m/s

Solution

Acceleration = Force / Mass = 36 N / 12 kg = 3 m/s². Velocity = Initial velocity + (Acceleration × Time) = 0 + (3 m/s² × 3 s) = 9 m/s.

Correct Answer: C — 3 m/s

Q. A 12 kg object is moving with a velocity of 3 m/s. What is its momentum? (2019)

A. 36 kg·m/s
B. 12 kg·m/s
C. 9 kg·m/s
D. 24 kg·m/s

Solution

Momentum p = mv = 12 kg * 3 m/s = 36 kg·m/s.

Correct Answer: A — 36 kg·m/s

Q. A 12 kg object is pulled with a force of 48 N. If the frictional force is 12 N, what is the acceleration of the object? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 48 N - 12 N = 36 N. Acceleration a = F/m = 36 N / 12 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Q. A 15 kg box is pushed with a force of 60 N. If the frictional force is 15 N, what is the acceleration of the box? (2023)

A. 2 m/s²
B. 3 m/s²
C. 4 m/s²
D. 5 m/s²

Solution

Net force = 60 N - 15 N = 45 N. Acceleration a = F/m = 45 N / 15 kg = 3 m/s².

Correct Answer: B — 3 m/s²

Q. A 2 kg ball is dropped from a height of 10 m. What is its speed just before it hits the ground? (2022)

A. 14 m/s
B. 10 m/s
C. 20 m/s
D. 15 m/s

Solution

Using energy conservation, v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 10 m) = 14 m/s.

Correct Answer: A — 14 m/s

Q. A 2 kg ball is dropped from a height of 10 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 10 m/s
B. 14 m/s
C. 20 m/s
D. 15 m/s

Solution

Using conservation of energy, Potential Energy at height = Kinetic Energy just before hitting ground. mgh = 1/2 mv^2. Solving gives v = sqrt(2gh) = sqrt(2 * 10 m/s² * 10 m) = 14.14 m/s.

Correct Answer: A — 10 m/s

Q. A 2 kg ball is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 10 m/s
B. 20 m/s
C. 15 m/s
D. 5 m/s

Solution

Using energy conservation, Potential Energy = Kinetic Energy at the ground: mgh = 0.5 mv^2; v = sqrt(2gh) = sqrt(2 * 10 m/s² * 20 m) = 20 m/s

Correct Answer: B — 20 m/s

Q. A 2 kg block slides down a frictionless incline of height 3 m. What is its speed at the bottom? (2023)

A. 6 m/s
B. 3 m/s
C. 4 m/s
D. 5 m/s

Solution

Using conservation of energy, Potential Energy at top = Kinetic Energy at bottom: mgh = 1/2 mv^2; v = sqrt(2gh) = sqrt(2 * 9.8 m/s² * 3 m) = 7.75 m/s (approx. 6 m/s)

Correct Answer: A — 6 m/s

Q. A 2 kg mass is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 10 N
C. 20 N
D. 0 N

Solution

The force acting on it is its weight, F = mg = 2 kg × 10 m/s² = 20 N.

Correct Answer: B — 10 N

Q. A 2 kg object is dropped from a height of 20 m. What is its speed just before it hits the ground? (g = 10 m/s²) (2023)

A. 20 m/s
B. 10 m/s
C. 15 m/s
D. 5 m/s

Solution

Using the formula v = √(2gh) = √(2 * 10 m/s² * 20 m) = √400 = 20 m/s

Correct Answer: A — 20 m/s

Q. A 2 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (2022)

A. 2 N
B. 9.8 N
C. 19.6 N
D. 29.4 N

Solution

The force acting on the object is its weight, F = mg = 2 kg × 9.8 m/s² = 19.6 N.

Correct Answer: C — 19.6 N

Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (2020)

A. 60 J
B. 30 J
C. 20 J
D. 10 J

Solution

Work Done (W) = m * g * h = 2 kg * 9.8 m/s^2 * 3 m = 58.8 J (approx. 60 J)

Correct Answer: B — 30 J

Q. A 2 kg object is lifted to a height of 3 m. What is the work done against gravity? (g = 9.8 m/s²) (2023)

A. 58.8 J
B. 19.6 J
C. 29.4 J
D. 39.2 J

Solution

Work Done = mgh = 2 kg * 9.8 m/s² * 3 m = 58.8 J

Correct Answer: A — 58.8 J

Q. A 2 kg object is moving with a velocity of 10 m/s. What is its momentum? (2021)

A. 5 kg·m/s
B. 10 kg·m/s
C. 15 kg·m/s
D. 20 kg·m/s

Solution

Momentum = Mass × Velocity = 2 kg × 10 m/s = 20 kg·m/s.

Correct Answer: D — 20 kg·m/s

Q. A 2 kg object is moving with a velocity of 4 m/s. What is its kinetic energy? (2023)

A. 16 J
B. 8 J
C. 4 J
D. 32 J

Solution

Kinetic Energy (KE) = 1/2 * m * v^2 = 1/2 * 2 kg * (4 m/s)^2 = 16 J.

Correct Answer: A — 16 J

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