Circle Equation | JEE Main Maths #Shorts
“Let’s read the question carefully.” “A circle is defined by the equation x square plus y square minus ten x plus six y plus twenty-five equals zero.” “We are asked to find the radius of the circle.” “The options are given below. Let’s solve this step by step and verify.”
“First, recall the standard equation of a circle.” “It is written as x minus h whole square plus y minus k whole square equals r square.” “Once the equation is in this form, the radius can be found directly.”
“Now, let’s focus on the x-terms.” “We have x square minus ten x.” “By completing the square, this becomes x minus five whole square.” “This step helps us convert the equation into standard form.”
“Next, we complete the square for the y-terms.” “y square plus six y becomes y plus three whole square.” “Now both x and y parts are in squared form.”
“After rearranging, the equation becomes—” “x minus five whole square plus y plus three whole square equals nine.” “This is now the standard equation of a circle.”
“Here, r square is equal to nine.” “So the radius r is equal to three.” “Looking at the options, option D is the correct answer.”
