Acceleration due to gravity (g) is the acceleration produced in a body due to the gravitational pull of the Earth when it falls freely towards the Earth.
Acceleration due to gravity is the acceleration of a freely falling body under the influence of Earth's gravitational force.
Near the surface of the Earth, the value of acceleration due to gravity is:
g = 9.8 m s−2
For numerical problems in CET, we usually take:
g = 10 m s−2
Acceleration due to gravity is related to Newton’s law of gravitation as:
g = G M / R2
where,
M = mass of the Earth
R = radius of the Earth
| g | G |
|---|---|
| Acceleration due to gravity | Universal gravitational constant |
| Varies from place to place | Constant everywhere |
| Unit: m s-2 | Unit: N m2 kg-2 |
Q1. Acceleration due to gravity is denoted by: A) G B) g C) a D) F Answer: B Q2. SI unit of acceleration due to gravity is: A) m s⁻¹ B) m s⁻² C) N kg⁻¹ D) kg m s⁻² Answer: B Q3. Value of g near the surface of Earth is approximately: A) 9.8 m s⁻¹ B) 10 m s⁻¹ C) 9.8 m s⁻² D) 10 m s⁻² Answer: C Q4. Acceleration due to gravity depends on: A) Mass of the body B) Shape of the body C) Mass and radius of Earth D) Volume of the body Answer: C Q5. Formula relating g with G is: A) g = G R / M B) g = G M / R² C) g = M / G R² D) g = R² / G M Answer: B Q6. Acceleration due to gravity is: A) Same for all bodies at a place B) Different for different masses C) Zero everywhere D) Maximum in space Answer: A Q7. Which quantity remains constant everywhere in the universe? A) g B) Weight C) Acceleration D) G Answer: D Q8. Acceleration due to gravity acts: A) Away from Earth B) Towards the centre of Earth C) Horizontally D) Randomly Answer: B
Acceleration produced in a body due to Earth's gravitational pull.
g = 9.8 m s−2 (≈ 10 m s−2 for numericals)
g = G M / R2
Direct MCQs and numericals are asked on value of g, its direction and relation with G.
