Topic 12: CET-Level Numerical Problems

Q1. A body of mass 2 kg is moving with a velocity of 5 m/s.
Find its momentum.
A) 2 kg m/s
B) 5 kg m/s
C) 7 kg m/s
D) 10 kg m/s

Answer: D


Q2. A force of 10 N acts on a body of mass 2 kg.
What is the acceleration produced?
A) 2 m/s²
B) 5 m/s²
C) 10 m/s²
D) 20 m/s²

Answer: B


Q3. A body of mass 1 kg changes its velocity from 4 m/s to 10 m/s
in 2 seconds. Find the impulse.
A) 6 N s
B) 10 N s
C) 14 N s
D) 20 N s

Answer: C


Q4. A ball of mass 0.5 kg moving with velocity 8 m/s comes to rest.
Find the change in momentum.
A) 0 kg m/s
B) 2 kg m/s
C) 4 kg m/s
D) 8 kg m/s

Answer: C


Q5. Two bodies of masses 2 kg and 3 kg move with velocities
4 m/s and 2 m/s respectively in the same direction.
Find total momentum.
A) 8 kg m/s
B) 14 kg m/s
C) 16 kg m/s
D) 20 kg m/s

Answer: B


Q6. A force of 20 N acts for 0.5 s on a body.
Find the impulse.
A) 5 N s
B) 10 N s
C) 20 N s
D) 40 N s

Answer: B


Q7. A body of mass 4 kg initially at rest attains a velocity
of 6 m/s. Find the change in momentum.
A) 6 kg m/s
B) 12 kg m/s
C) 24 kg m/s
D) 30 kg m/s

Answer: C


Q8. In a collision, if no external force acts,
which quantity remains conserved?
A) Velocity
B) Force
C) Momentum
D) Acceleration

Answer: C

Chapter 2: Laws of Motion

Topic 12: Numerical Problems – Quick Revision

1. Key Formulas

• p = m × v
• F = m × a
• I = F × t = change in momentum

2. Units

• Momentum → kg m s^-1
• Force → newton (N)
• Impulse → N s

3. Conservation of Momentum

Total momentum before interaction = total momentum after interaction (if no external force acts).

4. CET Tips

• Numericals are usually 1-step
• Watch units carefully
• Direct formula substitution is enough

Exam Focus (MHT-CET)

At least 1–2 questions are asked directly from numericals based on laws of motion.