A simple pendulum consists of a small heavy bob suspended from a rigid support by a light, inextensible string.
When the bob is displaced slightly from its mean position and released, it oscillates to and fro.
For small oscillations, the motion of a simple pendulum is simple harmonic.
The time period of a simple pendulum is given by:
T = 2π √(L / g)
where,
L = length of the pendulum (m)
g = acceleration due to gravity (m s−2)
Q1. A simple pendulum consists of: A) Heavy string and light bob B) Light string and heavy bob C) Elastic string and bob D) Rigid rod and bob Answer: B Q2. Time period of a simple pendulum depends on: A) Mass of bob B) Amplitude C) Length of pendulum D) Shape of bob Answer: C Q3. Formula for time period of a simple pendulum is: A) T = 2π √(g / L) B) T = π √(L / g) C) T = 2π √(L / g) D) T = √(L / g) Answer: C Q4. Time period of a simple pendulum is independent of: A) Length B) Gravity C) Mass of bob D) Value of π Answer: C Q5. If length of a pendulum is doubled, its time period becomes: A) Double B) Half C) √2 times D) 2√2 times Answer: C Q6. If g increases, the time period of pendulum: A) Increases B) Decreases C) Remains same D) Becomes zero Answer: B Q7. Simple pendulum performs SHM when oscillations are: A) Large B) Very large C) Small D) Random Answer: C Q8. Unit of length in pendulum formula is: A) cm B) mm C) meter D) km Answer: C
A heavy bob suspended by a light, inextensible string.
T = 2π √(L / g)
Numericals are frequently asked on change in time period due to change in length or gravity.