The time period (T) of a simple harmonic motion is the time taken by a particle to complete one full oscillation.
The frequency (f) of SHM is the number of oscillations completed per second.
f = 1 / T
T = 1 / f
For a mass m attached to a spring of force constant k:
T = 2π √(m / k)
For small oscillations of a simple pendulum of length L:
T = 2π √(L / g)
Q1. Time period of SHM is the time taken for: A) Half oscillation B) One full oscillation C) One vibration only D) Mean to extreme Answer: B Q2. SI unit of time period is: A) Hertz B) Second C) Minute D) Radian Answer: B Q3. SI unit of frequency is: A) Second B) Radian C) Hertz D) Meter Answer: C Q4. Relation between frequency and time period is: A) f = T B) f = T² C) f = 1 / T D) f = 2πT Answer: C Q5. Time period of a mass–spring system depends on: A) Amplitude B) Mass and spring constant C) Velocity D) Displacement only Answer: B Q6. Formula for time period of simple pendulum is: A) T = 2π √(g / L) B) T = 2π √(L / g) C) T = π √(L / g) D) T = √(L / g) Answer: B Q7. If time period of a pendulum increases, its frequency: A) Increases B) Decreases C) Remains same D) Becomes zero Answer: B Q8. Time period of SHM is independent of: A) Mass B) Length C) Amplitude D) Force constant Answer: C
Time taken to complete one full oscillation.
Number of oscillations per second.
f = 1 / T
Mass–spring system: T = 2π √(m / k)
Simple pendulum: T = 2π √(L / g)
Numericals are frequently asked using formulas for pendulum and spring–mass system.