Arithmetic Aptitude for Competitive Exam Success

Arithmetic Aptitude

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Q. What is the value of log10(100)?

A. 1
B. 2
C. 3
D. 0

Solution

log10(100) = 2 because 10^2 = 100.

Correct Answer: B — 2

Q. What is the value of log10(1000)?

A. 1
B. 2
C. 3
D. 4

Solution

log10(1000) = log10(10^3) = 3.

Correct Answer: C — 3

Q. What is the value of log10(50) approximately?

A. 1.5
B. 1.7
C. 1.9
D. 2.0

Solution

log10(50) is approximately 1.7.

Correct Answer: B — 1.7

Q. What is the value of log2(1/8)?

A. -2
B. -3
C. -4
D. -5

Solution

1/8 = 2^-3, so log2(1/8) = -3.

Correct Answer: B — -3

Q. What is the value of log2(32)?

A. 4
B. 5
C. 6
D. 7

Solution

log2(32) = log2(2^5) = 5.

Correct Answer: B — 5

Q. What is the value of log2(8) + log2(4)?

A. 3
B. 4
C. 5
D. 6

Solution

log2(8) = 3 and log2(4) = 2, so 3 + 2 = 5.

Correct Answer: B — 4

Q. What is the value of log4(16)?

A. 1
B. 2
C. 3
D. 4

Solution

log4(16) = log4(4^2) = 2.

Correct Answer: B — 2

Q. What is the value of log5(25)?

A. 1
B. 2
C. 3
D. 4

Solution

log5(25) = log5(5^2) = 2.

Correct Answer: B — 2

Q. What is the value of log7(49)?

A. 1
B. 2
C. 3
D. 4

Solution

log7(49) = log7(7^2) = 2.

Correct Answer: B — 2

Q. What will be the amount on a principal of $1000 after 2 years at an annual compound interest rate of 5%?

A. $1102.50
B. $1050.00
C. $1200.00
D. $1150.00

Solution

Amount = P(1 + r)^n = 1000(1 + 0.05)^2 = 1000(1.1025) = $1102.50

Correct Answer: A — $1102.50

Q. What will be the compound interest on $1500 for 4 years at a rate of 10% per annum?

A. $600
B. $700
C. $800
D. $900

Solution

CI = A - P; A = P(1 + r)^n = 1500(1 + 0.10)^4 = 1500(1.4641) = $2196.15, CI = 2196.15 - 1500 = $696.15.

Correct Answer: C — $800

Q. What will be the compound interest on $4000 at an annual interest rate of 9% for 2 years?

A. $720.00
B. $800.00
C. $900.00
D. $850.00

Solution

Compound Interest = 4000(1 + 0.09)^2 - 4000 = 4000(1.1881) - 4000 = 752.40

Correct Answer: B — $800.00

Q. What will be the compound interest on an amount of $2000 at an annual interest rate of 5% for 3 years?

A. $315.25
B. $300.00
C. $250.00
D. $200.00

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 2000(1 + 0.05/1)^(1*3) - 2000 = 2000(1.157625) - 2000 = 315.25

Correct Answer: A — $315.25

Q. Which decimal represents 7/10?

A. 0.5
B. 0.7
C. 0.8
D. 0.9

Solution

7/10 equals 0.7.

Correct Answer: B — 0.7

Q. Which of the following fractions is equivalent to 0.3?

A. 1/3
B. 2/5
C. 3/10
D. 1/4

Solution

0.3 = 3/10.

Correct Answer: C — 3/10

Q. Which of the following is equal to 0.03?

A. 3/100
B. 1/30
C. 1/3
D. 3/10

Solution

0.03 = 3/100.

Correct Answer: A — 3/100

Q. Which of the following is equal to 0.33?

A. 1/3
B. 1/4
C. 1/2
D. 2/3

Solution

0.33 is approximately equal to 1/3.

Correct Answer: A — 1/3

Q. Which of the following is equal to 0.6?

A. 3/5
B. 2/3
C. 1/2
D. 4/5

Solution

0.6 = 6/10 = 3/5 after simplification.

Correct Answer: A — 3/5

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